A transformer has 500 turns of the primary winding and 10 turns of the secondary winding. Determine the secondary voltage if the secondary circuit is open and the primary voltage is 120 V.

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The primary winding of a step-up transformer has 110V ac across it. What is the secondary voltage if the turns ratio is 8?

The correct option is C 880VTurns ratio, n=NsNp=VsVp where p for primary coil and s for secondary coil. So, 8=VsVp or Vs=Vp×8=110×8=880V

The primary winding of a step-up transformer has $110 V$ ac across it. What is the secondary voltage if the turns ratio is $8$ ?

The correct option is C $880 V$
Turns ratio, $n = \frac{N_{s}}{N_{p}} = \frac{V_{s}}{V_{p}}$ where p for primary coil and s for secondary coil.
So, $8 = \frac{V_{s}}{V_{p}}$ or $V_{s} = V_{p} \times 8 = 110 \times 8 = 880 V$