Choose the correct option-162- 2-3-3-3-3-7-625-5-5-5-5-5-72 - 2-2-2-3-3-3-105-3-5-7-

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Standard VI

Mathematics

Prime Factorization

Choose the co...

Question

Choose the correct option.

72 = 2×2×2×3×3×3

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105=3×5×7

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625=5×5×5×5×5

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162= 2×3×3×3×3×7

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Solution

The correct option is B
105=3×5×7

72 = 2 × 2 × 2 × 3 × 3

105 = 3 × 5 × 7

625 = 5 × 5 × 5 × 5

162 = 2 × 3 × 3 × 3 × 3

Hence, only the factorisation of 105 is correct

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Similar questions

Simplify :

(i) $\frac{3 \sqrt{2} - 2 \sqrt{3}}{3 \sqrt{2} + 2 \sqrt{3}} + \frac{\sqrt{12}}{\sqrt{3} - \sqrt{2}}$

(ii) $\frac{7 + 3 \sqrt{5}}{3 + \sqrt{5}} - \frac{7 - 3 \sqrt{5}}{3 - \sqrt{5}}$

Question 6

Which of the following expressions show that rational numbers are associative under multiplication.
(a) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5}$
(b) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = \frac{2}{3} \times (\frac{3}{5} \times \frac{- 6}{7})$
(c) $\frac{2}{3} \times (\frac{- 6}{7} \times \frac{3}{5}) = (\frac{3}{5} \times \frac{2}{3}) \times \frac{- 6}{7}$
(d) $(\frac{2}{3} \times \frac{- 6}{7}) \times \frac{3}{5} = (\frac{- 6}{7} \times \frac{2}{3}) \times \frac{3}{5}$

Rationalise the denominator and simplify

(1)

(2)

(3)

(4)

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(12)

(13)

${(\frac{2}{3})}^{3} \times {(\frac{5}{7})}^{3}$ is equal to

$(a) {(\frac{2}{3} \times \frac{5}{7})}^{9}$
$(b) {(\frac{2}{3} \times \frac{5}{7})}^{6}$
$(c) {(\frac{2}{3} \times \frac{5}{7})}^{3}$
$(d) {(\frac{2}{3} \times \frac{5}{7})}^{0}$

Add (i) $(2 \sqrt{3} - 5 \sqrt{2}) a n d (\sqrt{3} + 2 \sqrt{2})$

(ii) $(2 \sqrt{2} + 5 \sqrt{3} - 7 \sqrt{5}) a n d (3 \sqrt{3} - \sqrt{2} + \sqrt{5})$

(iii) $(\frac{2}{3} \sqrt{7} - \frac{1}{2} \sqrt{2} + 6 \sqrt{11}) a n d (\frac{1}{3} \sqrt{7} + \frac{3}{2} \sqrt{2} - \sqrt{11})$

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Choose the correct option.

The correct option is B 105=3×5×7 72 = 2 × 2 × 2 × 3 × 3 105 = 3 × 5 × 7 625 = 5 × 5 × 5 × 5 162 = 2 × 3 × 3 × 3 × 3 Hence, only the factorisation of 105 is correct

The correct option is B
105=3×5×7

72 = 2 × 2 × 2 × 3 × 3

105 = 3 × 5 × 7

625 = 5 × 5 × 5 × 5

162 = 2 × 3 × 3 × 3 × 3

Hence, only the factorisation of 105 is correct