The principal solution of a trigonometric equation lies in the interval

-π2,π2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(- π, π)

No worries! We‘ve got your back. Try BYJU‘S free classes today!

[0, 2 π)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $[0, 2 π)$
The solution of a trigonometric equation that lies in the interval $[0, 2 π)$ is called the principal solution of the equation.

Suggest Corrections

Similar questions

sin 3 x = cos 2 x

(\frac{π}{2}, π)

(a) [- \frac{π}{2}, \frac{π}{2}] - \{0\} (b) [0, π] - \{\frac{π}{2}\} (c) (0, π) (d) (- \frac{π}{2}, \frac{π}{2})

(- \frac{π}{2}, \frac{π}{2}) (b) [0, π] - \{\frac{π}{2}\} (c) [- \frac{π}{2}, \frac{π}{2}] (d) [- \frac{π}{2}, \frac{π}{2}] - \{0\}

{sin}^{100} x - {cos}^{100} x = 1

n \in Z

[x]

\leq x

∣ ∣ ∣ ∣ ∣ \begin{matrix} [e] & [π] & [π^{2} - 6] [π] & π^{2} - 6 & [e] [π^{2} - 6] & [e] & [π] \end{matrix} ∣ ∣ ∣ ∣ ∣

Join BYJU'S Learning Program