The principal value branch of sec -1 isa - 2- - 2-0b 0- - 2c 0- -d -2-2

The principal value branch of sec minus;1x is 0, #160; #960; #960;2. Hence, the correct answer is option (b). ...

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Special Determinants

The principal...

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The principal value branch of sec^-1 is
$(a) [- \frac{π}{2}, \frac{π}{2}] - \{0\} (b) [0, π] - \{\frac{π}{2}\} (c) (0, π) (d) (- \frac{π}{2}, \frac{π}{2})$

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(- \frac{π}{2}, \frac{π}{2}) (b) [0, π] - \{\frac{π}{2}\} (c) [- \frac{π}{2}, \frac{π}{2}] (d) [- \frac{π}{2}, \frac{π}{2}] - \{0\}

(- \frac{π}{2}, \frac{π}{2}) (b) [- \frac{π}{2}, \frac{π}{2}] (c) (- \frac{π}{2}, \frac{π}{2}) - \{0\} (d) (0, π)

f (x) = {sec}^{- 1} x

If $\int_{0}^{π} x f (s i n x) d x = A \int_{0}^{\frac{π}{2}} f (s i n x) d x,$ then A=

M = \frac{π^{2}}{16 {sin}^{- 1} (- x)} + {cos}^{- 1} x

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