Question

The probability of getting a number greater than $2$ by throwing a fair dice is:

• A. $\frac{2}{3}$
• B. $\frac{1}{3}$
• C. $1$
• D. $\frac{3}{5}$

Answer 1

Answer: (A)

$\frac{2}{3}$

S = {1, 2, 3, 4, 5, 6}
$n\left(S\right)=6$
$E=$event of getting a number greater than $2$.
$\therefore$ E = {3, 4, 5, 6} $\Rightarrow$ $n\left(E\right)=4$
Required prob $=P\left(E\right)=$ $\frac{n\left(E\right)}{n\left(S\right)}=\frac{4}{6}=\frac{2}{3}$