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Question

The probability of getting a total of 10 in a single throw of the dice is


A

19

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B

112

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C

16

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D

536

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Solution

The correct option is B

112


When two dices are thrown, there are (6×6)=36 outcomes.

The set of all these outcomes is the sample space given by

S = (1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6),

(2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6)

(3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6)

(4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6)

(5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)

(6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)

i.e., n(S) = 36

Let E be the event of getting a total score of 10

Then E = \{(4, 6), (5, 5), (6, 4)\}

n(E)=3

Hence, required probability =n(E)n(S)

=336=112


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