The product $^{'} A^{'}$ is:

C_{6} H_{5} C O C H_{3}

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C_{6} H_{5} C l

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C_{6} H_{5} C H O

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C_{6} H_{5} O H

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Solution

The correct option is C $C_{6} H_{5} C H O$
Acylchloride in presence of $B a S O_{4}$ hydrogenation gives Aldehyde. The above process is called as Rosenmunds reduction.

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Similar questions

Why C6H5CL forms Ortho, para product but C6H5CCl3 form meta product?

Draw the resonance structures for the following compounds. Show the electron shift using curved-arrow notation.

(a) C₆H₅OH (b) C₆H₅NO₂ (c) CH₃CH = CH – CHO

(d) C₆H₅CHO (e) (f)

C_{6} H_{5} O H + C C I_{4} (1) N a O H - ----- \to (2) H^{+}

C_{6} H_{5} C H O + H C H O O H^{⊝} - -- \to P r o d u c t

(C_{6} H_{5} C H O)

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