Question

The product "n” of three positive integers is 6 times their sum. If one of the numbers is the sum of the other two, then the sum of all possible value(s) of "n” is?

• A. 336
• B. 252
• C. 241
• D. 192

Answer 1

The correct option is A

336

Let the numbers be x,y, x+y.

Therefore xy(x+y) = 12(x+y). Hence, xy= 12.

So, (x,y) = (1,12), (2,6) or (3,4).

Hence "n" = 156, 96 or 84.

Sum "s" (of all possible values of n) = 336.