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Conductivity MP BP and Electronegativity (Group 2)

The product o...

Question

The product obtained on fusion of $B a S O_{4}$ and ${N a}_{2} C O_{3}$ is:

B a C O_{3}

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B a O

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B a {(O H)}_{2}

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B a H S O_{4}

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Solution

The correct option is C $B a C O_{3}$
When $B a S O_{4}$ and ${N a}_{2} C O_{3}$ are fused, $B a C O_{3}$ is obtained.
$B a S O_{4} + N a_{2} C O_{3} \to B a C O_{3} + 2 N a S O_{4}$

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