The product of $(2 x^{2} - 3 x + 1)$ and (x -3) is.equal to

2 x^{2} - 3 x^{2} - 3

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2 x^{2} - 2 x - 2

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2 x^{3} - 3 x^{2} - 3

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2 x^{3} - 9 x^{2} + 10 x - 3

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Solution

The correct option is C $2 x^{3} - 9 x^{2} + 10 x - 3$
$(2 x^{2} - 3 x + 1) (x - 3) = 2 x^{3} - 6 x^{2} - 3 x^{2} + 9 x + x - 3 = 2 x^{3} - 9 x^{2} + 10 x - 3$

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If polynomial= $2 x^{3} + 3 x^{2} - 2 x$ , Divisor= $x - 1$ and quotient = $2 x^{2} + 5 x + 3$ , what is the remainder ?

\begin{matrix} {lim}_{x \to 1} \frac{x^{2} - 3 x + 2}{x^{2} - 4 x + 3} {lim}_{x \to 2} \frac{x^{3} + x^{2} - 12}{x^{3} - x^{2} - x - 2} {lim}_{x \to \sqrt{2}} \frac{x^{2} + x \sqrt{2} - 4}{x^{2} - 3 x \sqrt{2} + 4} {lim}_{x \to 3} \frac{x^{3} - 3 x^{2} - x + 3}{x^{3} - 6 x^{2} + 9 x} \end{matrix}

f (x) = \sqrt{\frac{x^{4} - 2 x^{3} + 3 x^{2} - 2 x + 2}{2 x^{2} - 2 x + 1}}

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