CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The product of all roots of the equation (x25x+7)2(x2)(x3)=1 is

A
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
7
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
42
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 42
Given equation is
(x25x+7)2(x2)(x3)=1(x25x+7)2(x2)(x3)1=0
The given equation will be of form
x4+bx3+cx2+dx+e=0
So, the product of the roots =e
Putting x=0, we get the value of e
e=(7)2(2)(3)1=42
Product of the roots
=7×6=42

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Partially Filled Dielectrics
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon