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Question

The product of two consecutive natural numbers which are multiples of 3 is equal to 810. Find the two numbers.

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Solution

Let the two consecutive natural numbers which are multiples of 3 be 3x and 3(x+1)
Now, 3x(3x+3)=810
x2+x=90
x2+x90=0
(x+10)(x9)=0
x=9 or x=10
Rejecting negative value of x, because number are natural. We have x=9
Hence, the required numbers are 27 and 30

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