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Question

The product(s) formed when $H_{2} O_{2}$ reacts with disodium hydrogen phosphate is:

P_{2} O_{5}, {N a}_{3} P O_{4}

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{N a}_{2} H P O_{4} \cdot H_{2} O_{2}

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N a H_{2} P O_{4} \cdot H_{2} O

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{N a}_{2} H P O_{4} \cdot H_{2} O

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Solution

The correct option is B ${N a}_{2} H P O_{4} \cdot H_{2} O_{2}$
$N a_{2} H P O_{4} + H_{2} O_{2} \to N a_{2} H P O_{4} \cdot H_{2} O_{2}$

The product formed when $H_{2} O_{2}$ reacts with disodium hydrogen phosphate is $N a_{2} H P O_{4} \cdot H_{2} O_{2}$ .

Hence, option B is correct.

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