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Oxoacids of Halogens

The products ...

Question

The products obtained when chlorine gas reacts with cold and dilute aqueous NaOH are:-

C l O^{-}

and

C l O_{3}^{-}

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C l O_{2}^{-}

and

C l O_{3}^{-}

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C l^{-}

and

C l O^{-}

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C l^{-}

and

C l O_{3}^{-}

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Solution

The correct option is C $C l^{-}$ and $C l O^{-}$
$C l_{2} + 2 O H^{-} - -------- \to c o l d a n d d i l u t e C l^{-} + C l O^{-} + H_{2} O$

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Similar questions

N a O H

{3 C l}_{2} + {6 O H}^{-} ⟶ {5 C l}^{-} + {C l O}_{3}^{-} + {3 H}_{2} O

C l O^{-},

C l O_{2}^{-}, C l O_{3}^{-}, C l O_{4}^{-}

N a O H

C l O^{-} + C r O_{2}^{-} \to C l^{-} + C r O_{4}^{2 -}

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