The quantity which has the same dimensions as that of gravitational potential is

latent heat

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impulse

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angular acceleration

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planck's constant

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specific heat capacity

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Solution

The correct option is D latent heat
Dimensions of gravitational potential
$= \frac{D i m e n s i o n o f w o r k}{D i m e n s i o n o f m a s s}$
$= \frac{[M L^{2} T^{- 2}]}{[M]} = [L^{2} T^{- 2}]$
and dimension of latent heat
$= \frac{D i m e n s i o n o f [Q]}{D i m e n s i o n o f [M]}$
$= \frac{[M L^{2} T^{- 2}]}{[M]} = [L^{2} T^{- 2}]$

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