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The questions (i) to (v) refer to the following salt solutions listed A to F:
A. Copper nitrate
B. Iron (II) sulphate
C. Iron (III) chloride
D. Lead nitrate
E. Magnesium sulphate
F. Zinc chloride
(i) Which two solutions will give a white precipitate when treated with dilute hydrochloric acid followed by barium chloride solution?
(ii) Which two solutions will give a white precipitate when treated with dilute nitric acid followed by silver nitrate solution?
(iii) Which solution will give a white precipitate when either dilute hydrochloric acid or dilute sulphuric acid is added to it?
(iv) Which solution becomes a deep/inky blue colour when excess of ammonium hydroxide is added to it?
(v) Which solution gives a white precipitate with excess ammonium hydroxide solution?

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Solution

(i) Solution of iron (II) sulphate (B) and magnesium sulphate (E) will give a white precipitate on treatment with dilute hydrochloric acid followed by barium chloride solution as per the reactions given below:
FeSO4 + BaCl2BaSO4 + FeCl2
MgSO4 + BaCl2BaSO4 + MgCl2
(ii) Solution of iron (III) chloride (C) and zinc chloride (F) will give a white precipitate on treatment with dilute nitric acid and silver nitrate solution as per the reactions given below:
FeCl3 + AgNO33AgCl + Fe(NO3)3
ZnCl2 + AgNO33AgCl + Zn(NO3)2
(iii) Solution of lead nitrate (D) gives white precipitate of lead chloride or lead sulphate on treatment with dilute hydrochloric acid or sulphuric acid respectively:
Pb(NO3)2 + H2SO4PbSO4 + 2HNO3
Pb(NO3)2 + HClPbCl2 + 2HNO3
(iv) Solution of copper nitrate (A) forms deep blue coloured solution on treatment with excess of ammonium hydroxide solution:
Cu(NO3)2 + 2NH4OH →Cu(OH)2 + 2NH4NO3
(v) Zinc chloride gives a white precipitate on treatment with excess of ammonium hydroxide:
ZnCl2 + 2NH4OH → Zn(OH)2 + 2NH4Cl

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