Question

The quick return mechanism used in the shaper has rocker arm drive of length $200mm$. If the crank radius is $50mm$ and the offset between crank centre and rocker arm pivot is $20mm$, length of the stroke (in meters) is

• A. $0.5$
• B. $1.0$
• C. $1.5$
• D. $2.0$

Answer 1

The correct option is B $1.0$

Given data:
$OA=20mm,OB=50mmAC=200mm$

$\text{Length of the stroke}=\frac{2\times A\times OB}{OA}$

$=\frac{2\times 300\times 50}{20}$

$=1000mm=1m$