Question

The quotient when $6ab-b^2+12ac-2bc$ is divided by (61-b) is:

• A. b+2c
• B. b-2c
• C. 2b+c
• D. 2b-c

Answer 1

The correct option is A b+2c

$\frac{6ab-b^2+12ac-2bc}{(6a-b)}$
First expression
$6ab-b^2+12ac-2bc$
$=b(6a-b)+2c(6a-b)$
$=b(b+2c)(6a-b)$
$\Rightarrow \frac{6ab-b^2+12ac-2bc}{(6a-b)}$
$=\frac{(6a-b)(b+2c)}{(b+2c)}$
$=(b+2c)$