The radii of ...

Question

The radii of N, $N^{3 -}$ , O and $O^{2 -}$ are in the order:

O^{2 -} > N^{3 -} > O > N

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O^{2 -} > N^{3 -} > N > O

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N^{3 -} > O^{2 -} > N > O

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O^{2 -} > N^{3 -} > N

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Solution

The correct option is A $N^{3 -} > O^{2 -} > N > O$
The radii is larger for a negative charge carrying ion than the neutral element. Also size of elements decreases towards right in a period. Thus the correct order is $N^{3 -} > O^{2 -} > N > O$

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o A

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\circ A

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