Question

The radioactive decay of ${}_{35}{\text{X}}^{88}$ by $\beta$-emission produces an unstable nucleus, which spontaneously emits a neutron. The final product is :

• A. ${}_{37}{\text{X}}^{88}$
• B. ${}_{35}{\text{Y}}^{89}$
• C. ${}_{34}{\text{X}}^{88}$
• D. ${}_{36}{\text{W}}^{87}$

Answer 1

Answer: (D)

${}_{36}{\text{W}}^{87}$

$\beta$-emission followed by a neutron emission reduces mass by one unit and increases the atomic number by one unit so the product is ${}_{36}{\text{W}}^{87}$.