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Question

The radius of a shell for Hatom is 4.761oA. The value of n is:

A
3
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B
9
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C
5
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D
None of these
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Solution

The correct option is A 3
We know, Bhor's radius
rn=52.9n2 Pm (1)
As we are given,
rn=4.761˙A (2)
equating both the equations
4.761×1010=52.9n2×1010
n2=9
n=3


1195383_1340820_ans_82a6ad1e3ef24e149c0083ec4d5555d2.jpg

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