Question

The radius of curvature of a railway line at a place when the train is moving with a speed of $36kmh{r}^{-1}$ is $1000m$, the distance between the two rails being $1.5m$. The elevation of the outer rail above the inner rail is:

• A. $\frac{1.5}{98}$
• B. $\frac{3}{98}$
• C. $\frac{4.5}{98}$
• D. $\frac{1}{98}$

Answer 1

The correct option is A $\frac{1.5}{98}$

$Nsin\theta =\frac{m{v}^2}{r}$
$Ncos\theta =mg$
$tan\theta =\frac{v^2}{rg}$

if we define $h$ as the elevation,

$\frac{h}{1.5}=\frac{100}{1000\times 9.8}$

$h=\frac{1.5}{98}$