The radius of each plate in a parallel plate capacitor is 10cm . If the distance between the plates is $10 c m$ , then calculate the capacitance of capacitor filled with air .

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Solution

Radius of plate = $10 c m$ = $10 \times 10^{- 2} m$
Cross sectional area of plate ( $A$ ) = $π r^{2}$ $= π \times (10 \times 10^{- 2})^{2}$
Distance between plate ( $d$ ) = $10 c m$ = $10 \times 10^{- 2} m$
Capacitance of parallel plate capacitor :
$C = \frac{ε_{0} A}{d}$
$C = \frac{8.86 \times 10^{- 12} \times 3.14 \times (10 \times 10^{- 2})^{2}}{10 \times 10^{- 2}}$ = $2.78 \times 10^{- 12}$
$C = 2.78 p F$

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The radius of each plate in a parallel plate capacitor is 10cm . If the distance between the plates is 10cm , then calculate the capacitance of capacitor filled with air .

Radius of plate = 10cm = 10×10−2mCross sectional area of plate (A) = πr2 =π×(10×10−2)2Distance between plate (d) = 10cm = 10×10−2mCapacitance of parallel plate capacitor :C=ε0AdC=8.86×10−12×3.14×(10×10−2)210×10−2 = 2.78×10−12C=2.78pF

The radius of each plate in a parallel plate capacitor is 10cm . If the distance between the plates is $10 c m$ , then calculate the capacitance of capacitor filled with air .