CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Effect of Catalyst

The rate cons...

Question

The rate constant $K_{1}$ of a reaction is found to be double that of a rate constant $K_{2}$ of another reaction. The relationship between corresponding activation energies of the two reactions at same temperature $(E_{1}$ and $E_{2})$ can be represented as:

A

E_{1} > E_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

E_{1} < E_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C

E_{1} = E_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

none of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $E_{1} < E_{2}$
Arrhenius equation,
$K = A e^{- E_{a} / R T}$
Larger is rate constant, lesser is energy of activation so $E_{1} < E_{2}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The rate constant

(k_{1})

of one reaction is found to be double that of the rate constant of

(k_{2})

another reaction. Then the relationship between the corresponding activation energies of two reactions(

E_{1}

E_{2}

) can be represented as:

Q. The rate constant

(K_{1})

of one reaction is found to be double than that of the rate constant of

(K_{2})

another reaction. Then, the relationship between the corresponding activation energies of two reactions

(E_{1}

E_{2})

can be represented as:

Q. A reaction can take place by two paths.

k_{1}

k_{2}

are rate constants for the two paths &

E_{1}

E_{2}

are their respective activation energies.
At temperature

T_{a} : k_{1} > k_{2}, E_{1} < E_{2}

Its temperature is raised to

T_{b}

, the rate constants change to

k_{1}^{'}

k_{2}^{'}

. Which relation is correct between

k_{1}, k_{2}, k_{1}^{'}

k_{2}^{'}

(considering activation energy does not change with temperature)?

Q. At a certain temperature, the first order rate constant

k_{1}

is found to be smaller than the second order rate constant

k_{2}

. If the energy of activation

E_{1}

of the first order reaction is greater than energy of activation

E_{2}

of the second order reaction, then with increase in temperature:

Q. The rate constants

k_{1}

k_{2}

of two reactions are in the ratio 2:1 at some temperature and 1:1 at infinite temperature. The corresponding energies of activation of the two reactions will be related by:

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Effect of Catalyst

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Effect of Catalyst

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon