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Question

The rate of a reaction becomes four times when the temperature changes from 293K to 313 K. Calculate the energy of activation (Ea) of the reaction assuming that it does not change with temperature.
[R=8.314 JK1mol1,log 4=0.6021]


Solution

Let  k1=k, T1=293 K
k2=4k, T2=313 K
logk2k1=Ea2.303 R[T2T1T1T2]
log 4kk=Ea2.303×8.314[313293293×313]
log 4=Ea2.303×8.314[2091709]
0.6021=Ea×202.303×8.314×91709
Ea=6021×2.303×8.314×9170920
=52863 J mol1
=52.863 kJ mol1

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