The rate of a reaction is expressed in different ways as follows- 1-2 - d-C-dt -1-3 - d-D-dt -1-4 - d-A-dt - - d-B-dt- The reaction is4A-2B - 2C-3DB-1-2-D - 4A-3C4A-B - 2C-3DB-3D - 4A-2C

The correct option is D B+3D → 4A+2CB+3D→ 4A+2C d[B]/dt= 1/3d[D]/dt=1/4d[A]/dt=1/2d[C]/dt ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Rate of Reaction

The rate of a...

Question

The rate of a reaction is expressed in different ways as follows:
$\frac{1}{2} (\frac{d [C]}{d t}) = - \frac{1}{3} (\frac{d [D]}{d t}) = \frac{1}{4} (\frac{d [A]}{d t}) = - (\frac{d [B]}{d t})$
The reaction is

4 A + B \to 2 C + 3 D

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B + 3 D \to 4 A + 2 C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

4 A + 2 B \to 2 C + 3 D

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B + (1 / 2) D \to 4 A + 3 C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

I_{2} + 2 S_{2} O_{3}^{2 -} \to S_{4} O_{6}^{2 -} + 2 I^{⊖}

\frac{- d [I_{2}]}{d t} = - \frac{1}{2} \frac{d [S_{2} O_{3}^{2 -}]}{d t}

\frac{- d [I_{2}]}{d t} = - 2 \frac{d [S_{2} O_{3}^{2 -}]}{d t}

\frac{- d [I_{2}]}{d t} = - 2 \frac{d [I^{⊖}]}{d t} \frac{d [S_{2} O_{3}^{2 -}]}{d t}

\frac{d [S_{4} O_{6}^{2 -}]}{d t} = \frac{1}{2} \frac{d [I^{⊖}]}{d t}

\frac{1}{2} (\frac{d [C]}{d t}) = - \frac{1}{3} (\frac{d [D]}{d t}) = \frac{1}{4} (\frac{d [A]}{d t}) = - (\frac{d [B]}{d t})

+ \frac{1}{2} \frac{d [C]}{d t} = - \frac{1}{3} \frac{d [D]}{d t} = + \frac{1}{4} \frac{d [A]}{d t} = - \frac{d [B]}{d t}

\frac{1}{2} (\frac{d [C]}{d t}) = - \frac{1}{3} (\frac{d [D]}{d t}) = \frac{1}{4} (\frac{d [A]}{d t}) = - (\frac{d [B]}{d t})

= \frac{1}{2} \frac{d [C]}{d t} = - \frac{1}{3} \frac{d [D]}{d t} = \frac{1}{4} \frac{d [A]}{d t} = - \frac{d [B]}{d t}

Join BYJU'S Learning Program