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Question

The rate of a reaction quadruples when the temperature changes from 293K to 313K. Calculate the energy of activation of the reaction assuming that it does not change with temperature.

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Solution

The Arrhenius equation at two different temperatures is as follows:
log(kk)=Ea2.303R[1T1T]
kk=4
log(4)=Ea2.303×8.314[12931313]

The energy of activation, Ea=52863.3J/mol=52.86kJ/mol.

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