Question

# The rate of diffusion of methane at a given temperature is twice that of gas $$X$$. The molecular mass of gas $$X$$ is :

A
64.0
B
32.0
C
4.0
D
8.0

Solution

## The correct option is C $$64.0$$The rate of diffusion of methane at a given temperature is twice that of gas X. $$\displaystyle {r_{CH_4}} = 2{r_X}$$The rate of diffusion is inversely proportional to the square root of its molar mass.$$\displaystyle \dfrac {r_{CH_4}}{r_X}=\sqrt {\dfrac {M_X}{M_{CH_4}}}$$$$\displaystyle \dfrac {2r_X}{r_X}=\sqrt {\dfrac {M_X}{ 16}}$$$$\displaystyle 4= \dfrac {M_X}{ 16}$$The molecular mass of gas $$X$$ is $$\displaystyle M_X = 64.0$$  g/molHence, the correct option is A.Chemistry

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