The rate of reaction becomes $2$ times for every $10^{o} C$ rise in temperature. How the rate of reaction will increase when the temperature is increased from $30^{o} C$ to $80^{o} C$ ?

16

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32

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64

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128

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Solution

The correct option is B $32$
Since the rate of reaction doubles for every $10^{o} C$ rise in temperature, hence for an increase in temperature by $80 - 30 = 50^{o} C$ , the rate of reaction will become $2^{5}$ = $32$ times

Hence, the correct option is $B$

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The rate of reaction becomes 2 times for every 10oC rise in temperature. How the rate of reaction will increase when the temperature is increased from 30oC to 80oC?

The correct option is B 32Since the rate of reaction doubles for every 10oC rise in temperature, hence for an increase in temperature by 80−30=50oC, the rate of reaction will become 25 =32 timesHence, the correct option is B

The rate of reaction becomes $2$ times for every $10^{o} C$ rise in temperature. How the rate of reaction will increase when the temperature is increased from $30^{o} C$ to $80^{o} C$ ?

The correct option is B $32$
Since the rate of reaction doubles for every $10^{o} C$ rise in temperature, hence for an increase in temperature by $80 - 30 = 50^{o} C$ , the rate of reaction will become $2^{5}$ = $32$ times

Hence, the correct option is $B$