Question

The ratio between potential energy and total energy of an electron in H-atom according to Bohr atom is ___________.

• A. 1 : -1
• B. 1 : 1
• C. 1 : 2
• D. 2 : 1

Answer 1

The correct option is D 2 : 1

$\frac{Z{e}^2}{4\pi {\epsilon }_0{r}^2}=\frac{m{v}^2}{r}$

Substituting the value of $v$, we get

$KE=\frac{m{v}^2}{2}=\frac{m{Z}^2{e}^4}{8{\epsilon }_0^2{h}^2{n}^2}$

$PE=\frac{-Z{e}^2}{4\pi {\epsilon }_0{r}^2}=\frac{-m{Z}^2{e}^4}{4{\epsilon }_0^2{h}^2{n}^2}$

$\frac{PE}{KE+PE}=2:1$

Hence, the correct option is $\text{D}$