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Question

The ratio in which the line 3x+4y+2=0 divides the distance between 3x+4y+5=0 and 3x+4y-5=0, is

A
7 : 3
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B
3 : 7
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C
2 : 3
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D
None of these
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Solution

The correct option is B 3 : 7
Lines 3x+4y+2=0 and 3x+4y+5=0 are on the same side of the origin. The distance between these lines is
d1=2532+42=35
Lines 3x+4y+2=0 and 3x+4y-5=0 are on the opposite sides of the origin. The distance between these lines is
d2=2+532+42=75
Thus 3x+4y+2=0 divides the distance between 3x+4y+5=0 and 3x+4y-5=0 in the ratio d1:d2 i.e., 3:7 .

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