Question

The ratio of molecular mass of two radioactive substances is$\frac{3}{2}$and the ratio of their decay constants is $\frac{4}{3}$.Then the ratio of their activity per mole will be

• A. 2
• B. $\frac{4}{3}$
• C. $\frac{4}{3}$
• D. $\frac{9}{8}$

Answer 1

The correct option is C

$\frac{4}{3}$

$A=-\frac{dN}{dt}=\lambda N\text{For one mole}A\alpha \lambda$