Question

The ratio of number of exchange pairs present in $d^9$ and magnetic moment of Cr in B.M. is:-

• A. $\frac{2}{\sqrt{3}}$
• B. $\frac{2\sqrt{3}}{3}$
• C. $\frac{2\sqrt{3}}{4}$
• D. $\frac{16}{\sqrt{35}}$

Answer 1

The correct option is A $\frac{2}{\sqrt{3}}$

Magnetic moment of $Cr$ in $d^9$:

$\mu =\sqrt{n(n+2)}$

$=\sqrt{1(1+2)}=\sqrt{3}$ (Refer to Image)

Two exchange pairs present in $d^9$ of $Cr$:

$\therefore \frac{2}{\sqrt{3}}$ .