Question

The ratio of number of $\sigma$ and $\pi$ bonds in benzene is:

• A. $2$
• B. $6$
• C. $4$
• D. $8$

Answer 1

The correct option is C $4$

The structure of benzene is
Total number of $\sigma$ bonds are 12 ( 6 $C-H$ and 6 $C-C$ ) and Total number of $\pi$ bonds $(C=C,bonds)$ are 3.
So, the ratio of number of sigma and pi bonds = $\frac{\sigma }{\pi }=\frac{12}{3}=4$