The ratio of pure and hybrid orbitals of H2C=CH_CH=CH2

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H_{2} C = C H - C H = C H_{2}

C_{6} H_{6}

C H_{2} = C H - C H_{2} - C H_{2} - C \equiv C H

C_{2} - C_{3}

C_{2} H_{4} + C L_{2} \to \dots \dots

C_{2} H_{5} B r + K O H (a l c .) Δ - \to \dots \dots

H_{2} C = C H_{2} + 2 [O] a l k . K M n O_{4} - ------ \to \dots \dots

H_{2} C = C H_{2} + H B r \to \dots \dots

H_{2} C = C H_{2} + O_{3} \to \dots \dots

The number of π and σ bonds present in H₂C=CHCH=CHCH₂ are:

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