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Question

The ratio of radius of $$2^{nd}$$ and $$3^{rd}$$ Bohr's orbit is:


A
3 : 2
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B
9 : 4
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C
2 : 3
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D
4 : 9
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Solution

The correct option is D 4 : 9
We know that the radius of an orbit in a hydrogen atom is directly proportional to $$n^2 $$. 

Therefore, the ratio of the radius of $$2^{nd}$$ orbit to the radius of $$3^{rd}$$ orbit $$= \dfrac{2^2}{3^2} = \dfrac 49$$.

Hence, option D is correct.

Chemistry

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