The ratio of the kinetic energy and the potential energy of electron in the hydrogen atom will be

1 : 2

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- 1 : 2

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2 : 1

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- 2 : 1

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Solution

The correct option is A $- 1 : 2$
The potential energy of electron in hydrogen atom is $- 27.2 e V$ and its kinetic energy is $+ 13.6 e V$ .
The ratio of the kinetic energy and the potential energy of electron in the hydrogen atom is:
$\frac{E_{k}}{E_{p}} = \frac{13.6}{(- 27.2)}$
$\frac{E_{k}}{E_{p}} = - \frac{1}{2}$

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