CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The ratio of the maximum velocity and maximum displacement of a particle executing SHM is equal to


A
n
loader
B
g
loader
C
T
loader
D
ω
loader

Solution

The correct option is D $$\omega$$
$$x=Asin(\omega t + \theta)$$, thus maximum x occurs at maximum value of sine, i.e. 1, which is x=A
$$v=dx/dt=A\omega cos(\omega t + \theta)$$, thus maximum v occurs at maximum value of cosine, i.e. 1, which is $$v=A\omega$$
Thus, ratio is $$A\omega/A=\omega$$

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image