Question

# The ratio of the maximum velocity and maximum displacement of a particle executing SHM is equal to

A
n
B
g
C
T
D
ω

Solution

## The correct option is D $$\omega$$$$x=Asin(\omega t + \theta)$$, thus maximum x occurs at maximum value of sine, i.e. 1, which is x=A$$v=dx/dt=A\omega cos(\omega t + \theta)$$, thus maximum v occurs at maximum value of cosine, i.e. 1, which is $$v=A\omega$$Thus, ratio is $$A\omega/A=\omega$$Physics

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