Question

# The ratio of the radii of gyration of a circular disc about a tangential axis in the plane of the disc and of a circular ring of the same radius about a tangential axis in the plane of the ring is

A
2:1
B
5:6
C
2:3
D
1:2

Solution

## The correct option is A $$\sqrt {5} : \sqrt {6}$$$$I_{disk}$$ = $$\frac{5}{4}MR^{2}$$ = $$MK_{disk}^{2}$$$${I_{ring}} = \frac{3}{2}M{R^2} = \ MK_{ring}^2$$$$= \dfrac{{{K_{disk}}}}{{{K_{ring}}}} = \sqrt {\dfrac{5}{6}}$$Physics

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