Question

The ratio of the weights of a man in a stationary lift and in a lift accelerating downward with a uniform acceleration '$a$' is $3:2$. The acceleration of the lift is:

• A. $\frac{g}{3}$
• B. $\frac{g}{2}$
• C. $g$
• D. $2g$

Answer 1

The correct option is A $\frac{g}{3}$

Consider W1 is the weight of the man in the stationary lift.

Consider W2 is the weight of the man in a lift accelerating downward.

$\frac{W_1}{W_2}=\frac{mg}{m(g-a)}=\frac{3}{2}$

$\frac{g}{g-a}=\frac{3}{2}\Rightarrow 2g=3g-3a\Rightarrow 3a=g$

$a=\frac{g}{3}$