The ratio of thermal conductivity of two rods of different material is 5 : 4. The two rods of same area of cross-section and same thermal resistance will have the lengths in the ratio

4 : 5

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9 : 1

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1 : 9

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5 : 4

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Solution

The correct option is D
5 : 4

Given $A_{1} = A_{2}$ and $\frac{K_{1}}{K_{2}} = \frac{5}{4}$

$∵ R_{1} = R_{2} ∴ \frac{l_{1}}{K_{1} A} = \frac{l_{2}}{K_{2} A} \Rightarrow \frac{l_{1}}{l_{2}} = \frac{K_{1}}{K_{2}} = \frac{5}{4}$ .

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The ratio of thermal conductivity of two rods of different material is 5 : 4. The two rods of same area of cross-section and same thermal resistance will have the lengths in the ratio

The correct option is D 5 : 4 Given A1=A2 and K1K2=54 ∵R1=R2∴l1K1A=l2K2A⇒l1l2=K1K2=54 .

The correct option is D
5 : 4

Given $A_{1} = A_{2}$ and $\frac{K_{1}}{K_{2}} = \frac{5}{4}$

$∵ R_{1} = R_{2} ∴ \frac{l_{1}}{K_{1} A} = \frac{l_{2}}{K_{2} A} \Rightarrow \frac{l_{1}}{l_{2}} = \frac{K_{1}}{K_{2}} = \frac{5}{4}$ .