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Question

The rationalising factor of $$\sqrt [3]{49}$$ is


A
49
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B
37
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C
0
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D
none
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Solution

The correct option is B $$\sqrt [3]{7}$$
 $$\sqrt [3]{49}= \left ( \sqrt{\left (  7\right )^{2}} \right )^{\frac{1}{3}} =\sqrt[3]{7}$$

Mathematics

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