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Stoichiometry

The reaction ...

Question

The reaction between gaseous ${N H}_{3}$ and $H B r$ produces a white solid ${N H}_{4} B r$ . Suppose that ${N H}_{3}$ and $H B r$ are introduced simultaneously into the opposite ends of an open tube of $1$ metre long. Where would you expect the white solid to form?

At a distance of

34.45 c m

from

{N H}_{3}

end

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At a distance of

68.5 c m

from

{N H}_{3}

end

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At a distance of

44.45 c m

from

H B r

end

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At a distance of

45.45 c m

from

H B r

end

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Solution

The correct option is C At a distance of $34.45 c m$ from ${N H}_{3}$ end

(Refer to Image)
Rate of diffusion $\propto \frac{1}{\sqrt{M_{o}}} \propto \frac{x (d i s t a n c e)}{\sqrt{M_{o}}}$
$∴ R_{d} = N H_{3} > H B r$
$∴ \frac{x}{\sqrt{M_{o} (N H_{3})}} = \frac{1 - x}{\sqrt{M_{o} (H B r)}}$
$\Rightarrow x = 68.5 c m$ , $1 - x = 34.45 c m$ .

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Similar questions

Q. The reaction between gaseous

N H_{3}

and

H B r

produces a white solid

N H_{4} B r

. Suppose a small quantity of gaseous

N H_{3}

and gaseous

H B r

are introduced simultaneously into opposite ends of an open tube which is one metre long. Calculate the distance of white solid formed from the end which was used to introduce

N H_{3}

A small quantity of gaseous $N H_{3}$ and HBr are introduced simultaneously into the opposite ends of an open tube that is 1m long. Calculate the distance of the white solid $N H_{4} B r$ formed from the end that was used to introduce $N H_{3}$ .

Q. Two gases NH₃ and HBr are introduced simultaneously into opposite ends of an open tube 1m long. The distance at which a ring of NH₄Br is formed from the NH₃ end is

N H_{3}

and

H C l

gas are introduced simultaneously from the two ends of a long tube. A white ring of

N H_{4} C l

appears first :

Q. At room temp,

N H_{3}

gas at one atm and

H C l

gas at

^{'} P^{'}

atm are allowed to effuse through identical pin holes to the opposite ends of a glass tube

1 m

long and uniform cross-section. A white deposit is observed at a distance of

60 c m

from the

H C l

end. What is

^{'} P^{'}

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The reaction between gaseous NH3 and HBr produces a white solid NH4Br. Suppose that NH3 and HBr are introduced simultaneously into the opposite ends of an open tube of 1 metre long. Where would you expect the white solid to form?

The correct option is C At a distance of 34.45cm from NH3 end(Refer to Image)Rate of diffusion ∝1√Mo∝x(distance)√Mo∴Rd=NH3>HBr∴x√Mo(NH3)=1−x√Mo(HBr)⇒x=68.5cm , 1−x=34.45cm.

The reaction between gaseous ${N H}_{3}$ and $H B r$ produces a white solid ${N H}_{4} B r$ . Suppose that ${N H}_{3}$ and $H B r$ are introduced simultaneously into the opposite ends of an open tube of $1$ metre long. Where would you expect the white solid to form?