1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# The reaction of burning of carbon in oxygen is represented by the equation:C(s)+O2(g)→CO2(g)+Heat+LightWhen 9.0 g of solid carbon is burnt in 16.0 g of oxygen gas, 22.0 g of carbon dioxide is produced. The mass of carbon dioxide gas formed on burning of 3.0 g of carbon in 32.0 g of oxygen would be (Note : atomic mass of C=12.0u,O=16.0u ):

A
6.60 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
7.33 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
8.25 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
11.00 g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is C 11.00 gC(s)+O2(g)→CO2(g)9 gm of C(s)=0.75 mole of C(s)16 g of O2(g) = 0.5 mole of O2(g)We know from the reaction that equal moles of C and O2 burn and form equal mole of CO2According to the question, 0.5 mole each of carbon and oxygen form 0.5 mole of CO2In the above process 0.25 mole (3 g) of Carbon left out. Left amount of carbon reacts with 32.0 g (1 mole ) of O2 to form 0.25 mole of CO2.Hence the amount of CO2 form = no. of moles × molecular mass of CO2 =0.25×44=11.0 gOption D is correct.

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Measurement of Significant Figures
CHEMISTRY
Watch in App
Explore more
Join BYJU'S Learning Program