The reaction of $C l_{2}$ gas with cold dilute and hot concentrated NaOH in water give sodium salt of two (different) oxoacids of chlorine P and Q respectively. The $C l_{2}$ gas reacts with $S O_{2}$ gas, in presence of charcoal to give a product R. R reacts with white phosphorous to give a compound S. On hydrolysis, S gives as oxoacid of phosphorous T.
P and Q, respectively, are the sodium salts of:

Hypochlorus and chloric acid

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Hypochlorus and chlorus acid

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Chloric and perchloric acids

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Chloric and hypochlorus acids.

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Solution

The correct option is A Hypochlorus and chloric acid
$C l_{2} + 2 N a O H (d i l . a n d c o l d) \to N a C l + N a O C l + H_{2} O$
$5 C l_{2} + 6 N a O H (c o n c . a n d h o t) \to 5 N a C l + N a C l O_{3} + 3 H_{2} O$

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The reactions of $C l_{2}$ gas with cold-dilute and hot-concentrated NaOH in water give sodium salts of two different oxoacids of chlorine, P and Q, respectively. The $C l_{2}$ gas reacts with $S O_{2}$ gas, in presence of charcoal, to give a product R reacts with white phosphorus to give a compound S. On hydrolysis, S gives an oxoacid of phosphorus.

3. P and Q, respectively, are the sodium salts of