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Question

The reaction of Cl2 gas with cold dilute and hot concentrated NaOH in water give sodium salt of two (different) oxoacids of chlorine P and Q respectively. The Cl2 gas reacts with SO2 gas, in presence of charcoal to give a product R. R reacts with white phosphorous to give a compound S. On hydrolysis, S gives an oxoacid of phosphorous T.
R, S and T, respectively are:

A
SO2Cl2,PCl5 and H3PO4
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B
SO2Cl2,PCl3 and H3PO3
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C
SOCl2,PCl3 and H3PO2
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D
SO2Cl2,PCl5 and H3PO4
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Solution

The correct option is A SO2Cl2,PCl5 and H3PO4
Cl2+SO2in presence of−−−−−−−charcoalSO2Cl210 SO2Cl2(R)+P44PCl5(S)+10 SO2PCl5(S)+4H2OH3PO4(T)+5HCl

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