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Question

The reaction of H3N3B3Cl3(A) with LiBH4 in tetrahydrofuran gives (B). Further, the reaction of (A) with (C) leads to H3N3B3(Me)3. Compounds (B) and (C) respectively, are:

A
Borazine and MeBr
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B
Borazine and MeMgBr
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C
Boron nitride and MeBr
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D
Diborane and MeMgBr
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