The reading of a pressure meter attached with a closed water pipe is 3.5 x 10 $^{5}$ N m $^{- 2}$ . On opening the valve of the pipe, the reading of pressure meter is reduced to 3 x 10 $^{5}$ N m $^{- 2}$ . Calculate the speed of water flowing in the pipe.

10 c m / s

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10 m / s

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0.1 m / s

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0.1 c m / s

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Solution

The correct option is C $10 m / s$

Applying Bernoulli's principle when the pipe was closed and after it was opened,
$\Rightarrow P_{1} = P_{2} + \frac{1}{2} ρ V^{2}$
$\Rightarrow 3.5 \times 10^{5} = 3 \times 10^{5} + \frac{1}{2} ρ V^{2}$
$\Rightarrow \frac{0.5 \times 10^{5} \times 2}{10^{3}} = V^{2}$
$\Rightarrow 10^{2} = V^{2} \Rightarrow V = 10 m / s$

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The reading of a pressure meter attached with a closed water pipe is 3.5 x 105 N m−2. On opening the valve of the pipe, the reading of pressure meter is reduced to 3 x 105 N m−2. Calculate the speed of water flowing in the pipe.

The correct option is C 10m/s Applying Bernoulli's principle when the pipe was closed and after it was opened,⇒P1=P2+12ρV2⇒3.5×105=3×105+12ρV2⇒0.5×105×2103=V2⇒102=V2⇒V=10m/s

The reading of a pressure meter attached with a closed water pipe is 3.5 x 10 $^{5}$ N m $^{- 2}$ . On opening the valve of the pipe, the reading of pressure meter is reduced to 3 x 10 $^{5}$ N m $^{- 2}$ . Calculate the speed of water flowing in the pipe.