Question

The reading of Centigrade thermometer coincides with that of Fahrenheit thermometer in a liquid. The temperature of the liquid is.

• A. $-{40}^{\circ }C$
• B. $0^{\circ }C$
• C. ${100}^{\circ }C$
• D. ${300}^{\circ }C$

Answer 1

Answer: (A)

$-{40}^{\circ }C$

$\frac{x-32}{180}=\frac{x}{100}$
$x=-{40}^{o}C$