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Question

The real number k for which the equation 2x3+3x+k=0 has two dinstinct real roots in [0,1] :


Your Answer
A
lies between 1 and 2
Your Answer
B
lies between 2 and 3
Your Answer
C
lies between 1 and 0
Correct Answer
D
does not exist

Solution

The correct option is D does not exist
Let f(x)=2x3+3x+k
f(x)=6x2+3>0    kR
Thus, f(x) is strictly increasing function
Hence, f(x)=2x3+3x+k=0 has only one real root, so two roots are not possible.

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